Majority Number III
Written on October 21, 2015
Tweet
Given an array of integers and a number k, the majority number is the number that occurs more than 1/k of the size of the array.
public class Solution {
public int majorityNumber(ArrayList<Integer> nums, int k) {
if (nums == null || nums.size() == 0 || k > nums.size()) return -1;
//bug : nums.size() !!! not nums.size
HashMap<Integer, Integer> map = new HashMap<Integer,Integer>();
for (int n : nums) {
if (map.containsKey(n)){
map.put(n, map.get(n) + 1);
} else if (map.size() < k) {
map.put(n, 1);
} else {
ArrayList<Integer> keys = new ArrayList<Integer>();
for (int key : map.keySet()) {
keys.add(key);
}
for (int key : keys) {
int val = map.get(key);
if (val == 1) {
map.remove(key);
} else {
map.put(key, val - 1);
}
}
}
}
List<Integer> list = new ArrayList<>();
for (int key : map.keySet()) {
list.add(key);
}
map = new HashMap<>();
for (int num : nums) {
for (int key : list) {
if (num == key) {
map.put(key, map.getOrDefault(key, 0) + 1);
}
}
}//must count occurrences again
int count = 0, result = 0;
for (int key : map.keySet()) {
if (count < map.get(key)) {
count = map.get(key);
result = key;
}
}
return result;
}
}