62 - Unique Paths
Written on October 21, 2015
Tweet
A robot is located at the top-left corner of a m x n grid (marked ‘Start’ in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked ‘Finish’ in the diagram below). How many possible unique paths are there?
public class Solution {
/**
* @param n, m: positive integer (1 <= n ,m <= 100)
* @return an integer
*/
public int uniquePaths(int m, int n) {
if (m == 0 || n == 0) return 0;
int[][] dp = new int[m][n];
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
if (i == 0 || j == 0) {
dp[i][j] = 1; //这不是初始化,只是需要单独处理边界问题
} else {
dp[i][j] = dp[i-1][j] + dp[i][j-1];
}
}
}
return dp[m-1][n-1];
}
}
class Solution(object):
def uniquePaths(self, m, n):
"""
:type m: int
:type n: int
:rtype: int
"""
dp = [[0] * n for i in xrange(m)]
for i in xrange(m):
for j in xrange(n):
if i == 0 or j == 0:
dp[i][j] = 1
else:
dp[i][j] = dp[i][j - 1] + dp[i - 1][j]
return dp[-1][-1]