280 - Wiggle Sort
Written on October 29, 2015
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Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3]…. For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4].
public class Solution {
public void wiggleSort(int[] nums) {
for (int i = 1; i < nums.length; i++) {
if ((i % 2 == 1 && nums[i] < nums[i - 1]) || (i % 2 == 0 && nums[i] > nums[i - 1])) {
int tmp = nums[i];
nums[i] = nums[i - 1];
nums[i - 1] = tmp;
}
}
}
}
class Solution(object):
def wiggleSort(self, nums):
"""
:type nums: List[int]
:rtype: void Do not return anything, modify nums in-place instead.
"""
if not nums:
return
for i in xrange(1, len(nums)):
if (i % 2 == 0 and nums[i] > nums[i - 1]) or (i % 2 != 0 and nums[i] < nums[i - 1]):
nums[i], nums[i-1] = nums[i-1], nums[i]