Implement wildcard pattern matching with support for ‘?’ and ‘*’.

class Solution:
    def isMatch(self, s: str, p: str) -> bool:
        dp = [[False] * (len(p) + 1) for _ in range(len(s) + 1)]
        dp[0][0] = True
        for j in range(1, len(p) + 1):
            if p[j - 1] == "*":
                dp[0][j] = True
            else:
                break

        for i in range(1, len(s) + 1):
            for j in range(1, len(p) + 1):
                if s[i - 1] == p[j - 1] or p[j - 1] == "?":
                    dp[i][j] = dp[i - 1][j - 1]
                elif p[j - 1] == "*":
                    dp[i][j] = dp[i - 1][j] or dp[i][j - 1]
        return dp[-1][-1]