44 - Wildcard Matching
Written on January 16, 2020
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Implement wildcard pattern matching with support for ‘?’ and ‘*’.
class Solution:
def isMatch(self, s: str, p: str) -> bool:
dp = [[False] * (len(p) + 1) for _ in range(len(s) + 1)]
dp[0][0] = True
for j in range(1, len(p) + 1):
if p[j - 1] == "*":
dp[0][j] = True
else:
break
for i in range(1, len(s) + 1):
for j in range(1, len(p) + 1):
if s[i - 1] == p[j - 1] or p[j - 1] == "?":
dp[i][j] = dp[i - 1][j - 1]
elif p[j - 1] == "*":
dp[i][j] = dp[i - 1][j] or dp[i][j - 1]
return dp[-1][-1]